Subject Test Math 2

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Subject Test Math 2

Question 6 of 28

In the $x y$ -plane, what is the area of a triangle whose vertices are $(\sqrt{2}, 0)$ , $(2, \sqrt{10})$ , and $(5, 0)$ ?

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$3.59$

Correct Answer:

No

$5.67$

Correct Answer:

Yes

$7.91$

Correct Answer:

No

$11.18$

Correct Answer:

No

$11.34$

Correct Answer:

No

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It is helpful to draw a sketch of the triangle:

The length of the base of the triangle is $5 - \sqrt{2}$ and the height of the triangle is $\sqrt{10}$ . Therefore, the area of the triangle is $\frac{1}{2} (5 - \sqrt{2}) (\sqrt{10}) ≃ 5.67$ . The correct answer is B.

Question Difficulty:

medium

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Subject Test Math 2

Question 6 of 28

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View Correct Answer