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Subject Test Math 2

Question 9 of 28

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SAT Subject Test

The function f is defined by f left parenthesis x right parenthesis equals fraction numerator 1 over denominator 4 end fraction x to the power of 3 end exponent minus fraction numerator 1 over denominator 2 end fraction x to the power of 2 end exponent minus fraction numerator 5 over denominator 4 end fraction x plus fraction numerator 3 over denominator 2 end fraction for negative 2 less or equal than x less or equal than 3.

What is the difference between the maximum and minimum values of f?

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1.04

Correct Answer: 
No

2.05

Correct Answer: 
No

2.91

Correct Answer: 
No

3.07

Correct Answer: 
Yes

5.00

Correct Answer: 
No

It is necessary to use your graphing calculator for this question. First graph the function y equals fraction numerator 1 over denominator 4 end fraction x to the power of 3 end exponent minus fraction numerator 1 over denominator 2 end fraction x to the power of 2 end exponent minus fraction numerator 5 over denominator 4 end fraction x plus fraction numerator 3 over denominator 2 end fraction. It is helpful to resize the viewing window so the x-values go from negative 2 to 3. On this interval the maximum value of f is 2.052 and the minimum value of f is negative 1.015. The difference between these two values is 3.067, which rounds to 3.07.

Question Difficulty: 
medium